ベンフォードの法則を確かめてみる

counts = []
(1..9).each {|i|counts[i] = 0}
rndf = RandomFloat.new :gt_or_eq => 1, :lt => 10000
100000.times {
        counts[rndf.rand.to_s[0, 1].to_i] += 1
}
(1..9).each {|i|print "%d %d\n" % [i, counts[i]]}

$ ruby19 random_float.rb
1 30194
2 16903
3 13305
4 9390
5 7751
6 6783
7 6451
8 4707
9 4516